Question
Question: Two balls carrying charges \( + 7\;{\rm{\mu C}}\) and \( - 5\;{\rm{\mu C}}\) attract each other with...
Two balls carrying charges +7μC and −5μC attract each other with a force F. If a charge −2μC is added to both, the force between them will be: -
(1) F
(2) 2F
(3) 2F
(4) Zero
Solution
Here, we will use the Coulomb's formula for attraction or repulsion force between two charges. If two charges have opposite signs then the force acting between them is attractive and if the two charges have the same sign then the force acting between the two charges is considered as repulsive force.
Complete step by step answer:
Given: The initial value of first charge is q1=+7μC and initial value of second charge is q2=−5μC. The force acting between the two charges is F. The new charge added to both charges is q=−2μC.
The formula for attraction or repulsion force between two charges is F1=kr2q1q2
Here, k is Coulomb's constant and r is the distance between the two charges.
Substituting the initial values of charge in above formula.
F=F1=kr27×(−5) F1=−35r2k
Now, a new charge is added to the initial values of first and second charge. Then, the obtained new values of first and second charges are,
q3=7−2 q3=5μC and q4=−5−2 q4=−7μC
Now, we substitute the obtained new value of both charges in Coulomb's formula to get the force between two charges,
F2=kr2q3q4 F2=kr25×(−7) F2=−35r2k
We can see that both the values of attraction force are the same and are equal to the initial value of force.
F=F1=F2
Therefore, the force between them will be F .
So, the correct answer is “Option 1”.
Note:
The attraction or repulsion force acting between two charges of different values is inversely proportional to the distance between the two charges. A new charge is added to the initial values of first and second charge.