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Question

Physics Question on System of Particles & Rotational Motion

Two balls are thrown simultaneously in air. The acceleration of the centre of mass of the two balls when in air,

A

depends on the masses of the two balls

B

depends on the speeds of the two balls

C

is equal to gg (Acceleration due to gravity)

D

depends on the direction of motion of the two balls.

Answer

is equal to gg (Acceleration due to gravity)

Explanation

Solution

We know that,
Acceleration of centre of mass
acm=m1a1+m2a2m1+m2a _{ cm }=\frac{m_{1} a _{1}+m_{2} a _{2}}{m_{1}+m_{2}}
Here, a1=a2=ga_{1}=a_{2}=g (Because balls are thiown in air i.e. under the gravity)
acm=m1g+m2gm1+m2a _{ cm }=\frac{m_{1} g+m_{2} g}{m_{1}+m_{2}}
acm=g(m1+m2)m1+m2a_{ cm }=\frac{g\left(m_{1}+m_{2}\right)}{m_{1}+m_{2}}
acm=ga _{ cm }=g