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Question

Physics Question on Moving charges and magnetism

Two 10 cm long, straight wires, each carrying a current of 5 A are kept parallel to each other. If each wire experienced a force of 10-5 N, then separation between the wires is _____ cm.

Answer

It should be mentioned, 10 cm wire is part of long wire.
Force experienced by unit length of wire

Fig. Force Experienced

=μ0I1I22πd×10×102= \frac{μ_0I_1I_2}{2πd} × 10 ×10^{-2}
105=2×107×5×5d×10×10210^{−5} = \frac{2×10−7×5×5}{d}×10×10−2
d=50×103md = 50 × 10^{–3} m
d=50×101cmd = 50 × 10^{–1} cm
d = 5 cm