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Question: Twenty molecule of \[{\text{ S}}{{\text{O}}_3}{\text{ }}\] will weigh as much as_______ molecule of ...

Twenty molecule of  SO3 {\text{ S}}{{\text{O}}_3}{\text{ }} will weigh as much as_______ molecule of oxygen.
A.100
B.50
C.15
D.8

Explanation

Solution

Calculate weight of given molecules of  SO3{\text{ S}}{{\text{O}}_3} first, then calculate the number of molecule of oxygen weight that much by using weight of 1 molecule of oxygen.

Complete step by step answer:
The mass/weight of smaller entities like atoms, molecules, and elements are expressed in atomic mass units (amu). However the mass of moles of atom, molecule or compound can be expressed in terms of gram. The atomic mass of Sulphur is 32 amu, that is mass of 1 atom of Sulphur weigh 32 amu and atomic mass of Oxygen is 16 amu that is mass of 1 atom of Oxygen weigh 16 amu. But the molecular mass of Oxygen is 32 amu, as Oxygen exists in O2{{\text{O}}_2} form, so 1 molecule of Oxygen will weigh 32 amu. Thereby we can calculate the mass of 1 molecule of  SO3{\text{ S}}{{\text{O}}_3} as =32+(16×3)=80 amu = 32 + \left( {16 \times 3} \right) = 80{\text{ amu}}.
The mass of 20 molecules of  SO3{\text{ S}}{{\text{O}}_3} is =80×20=1600 = 80 \times 20 = 1600.
As the mass of 1 molecule of oxygen is 32 amu. In order to find how many molecule of oxygen will weigh 1600 amu; we can do =160032=50 = \dfrac{{1600}}{{32}} = 50
That is 50 molecules of oxygen weigh as much as 20 molecules of  SO3{\text{ S}}{{\text{O}}_3}.
It is important to remember that the molecular mass of oxygen is 32amu and the atomic mass of oxygen is 16 amu. The molecule of oxygen is O2{{\text{O}}_2}, but the atom of oxygen is only  O {\text{ O }}.

Thus, option B is correct.

Note:
1 amu=1.67×1024gram 1{\text{ amu}} = 1.67 \times {10^{ - 24}}{\text{gram }}.In order for proper representation of mass/weight of smaller entities like atom or molecule; amu is used. But the moles of such entities can be represented in gram. 1 mole=6.022×10231{\text{ mole}} = 6.022 \times {10^{ - 23}} atoms, molecules or ions.