Question

Twelve wires, each of resistance 6Ω are connected to form a cube as shown in the adjoining figure. The current enters at a corner A and leaves at the diagonally opposite corner G.

The joint resistance across the corners A and G is

• A. 12 Ω
• B. 6 Ω
• C. 3 Ω
• D. 5 Ω

Answer 1

Answer: (D)

5 Ω

Answer 2

R_AG = $\frac{5}{6}$R = $\frac{5}{6}$× 6Ω = 5Ω