Question

Twelve tickets are numbered 1 to 12. One ticket is drawn at random, then the probability of the number to be divisible by 2 or 3, is

• A. $\frac { 2 } { 3 }$
• B. $\frac { 7 } { 12 }$
• C. $\frac { 5 } { 6 }$
• D. $\frac { 3 } { 4 }$

Answer 1

Answer: (A)

$\frac { 2 } { 3 }$

Answer 2

$P ( 2 \cup 3 ) = P ( 2 ) + P ( 3 ) - P ( 2 \cap 3 )$