Question

Turpentine oil is flowing through a capillary tube of length l and radius r. The pressure difference between the two ends of the tube is p. The viscosity of oil is given by :η = $\frac{p(r^{2} - x^{2})}{4v\mathcal{l}}$.Here v is the velocity of oil at a distance x from the axis of the tube. From this relation, the dimensional formula of η is-

• A. [ML^-1T^-1]
• B. [MLT^-1]
• C. [ML²T^-2]
• D. [M⁰L⁰T⁰]

Answer 1

Answer: (A)

$ML^-1T^-1$

Answer 2

η = $\frac{p(r^{2} - x^{2})}{4V\mathcal{l}}$ = $\frac{lM^{1}L^{- 1}T^{- 2}\rbrack\lbrack L^{2}\rbrack}{\lbrack L^{1}T^{- 1}\rbrack\lbrack L^{1}\rbrack}$