Question

Truth table for the given circuit in figure is.

• A. \begin{tabular} { c | c | c } $A$ & $B$ & $E$ \ \hline 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 0 \ \hline \end{tabular}
• B. \begin{tabular} { c | c | c } $A$ & $B$ & $E$ \ \hline 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \ 1 & 1 & 1 \ \hline \end{tabular}
• C.
• D. \begin{tabular} { c | c | c } $A$ & $B$ & $E$ \ \hline 0 & 0 & 0 \ 0 & 1 & 1 \ 1 & 0 & 1 \ 1 & 1 & 0 \ \hline \end{tabular}

Answer 1

Answer: (C)

Answer 2

: Truth table for the given circuit is

A	B	C=A.B	$D = \bar{A}.B$	E=C+D
0	0	0	0	0
0	1	0	1	1
1	0	0	0	0
1	1	1	0	1

Hence, option (3) is correct