Question
Question: Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of the two triangles, we have \[...
Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of the two triangles, we have PQAB=PMAD. If the above statement is true, then mention the answer as 1, else mention it as 0 if false.
Solution
Hint: To check if the given statement is true or not, use the fact that if two triangles are similar, then their angles are equal and the altitude of a triangle is perpendicular to its base. Use AA (Angle – Angle) Property to prove that ΔABD∼ΔPQM and thus, the ratio of length of sides of two triangles will be equal.
Complete step-by-step answer:
We have two similar triangles ΔABC and ΔPQR. AD and PM are altitudes of the two triangles. We have to check if the relation PQAB=PMAD holds or not.
As ΔABC∼ΔPQR, we know that the ratio of their corresponding sides is equal.
Thus, we have PQAB=PRAC=QRBC.
We will now consider the triangles ΔABD and ΔPQM.
We will prove that the two triangles are similar.
As AD is the altitude of ΔABC, we have AD⊥BD. So, we have ∠ADB=90∘.
Similarly, as PM is the altitude of ΔPQR, we have PM⊥QM. So, we have ∠PMQ=90∘.
Thus, ∠PMQ=∠ADB=90∘.
As we know that ΔABC∼ΔPQR. Thus, the corresponding angles of both the triangles are equal.
So, we have ∠PQM=∠ABD.
Thus, in ΔABD and ΔPQM, we have ∠PMQ=∠ADB=90∘ and ∠PQM=∠ABD.
Using AA (Angle – Angle) Property, we have ΔABD∼ΔPQM.
As ΔABD∼ΔPQM, the ratio of length of sides of both the triangles is equal.
Thus, we have PQAB=PMAD=QMBD.
So, the given statement is true.
Hence, the correct answer is 1.
Note: We can also prove that ΔABD∼ΔPQM by using the ASA (Angle Side Angle) Property as well. AA Property says that two corresponding angles of the triangles must be equal. ASA Property says that two corresponding angles and the sides between them of the two triangles must be equal.