Solveeit Logo

Question

Question: Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of the two triangles, we have \[...

Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of the two triangles, we have ABPQ=ADPM\dfrac{AB}{PQ}=\dfrac{AD}{PM}. If the above statement is true, then mention the answer as 1, else mention it as 0 if false.

Explanation

Solution

Hint: To check if the given statement is true or not, use the fact that if two triangles are similar, then their angles are equal and the altitude of a triangle is perpendicular to its base. Use AA (Angle – Angle) Property to prove that ΔABDΔPQM\Delta ABD\sim \Delta PQM and thus, the ratio of length of sides of two triangles will be equal.

Complete step-by-step answer:
We have two similar triangles ΔABC\Delta ABC and ΔPQR\Delta PQR. AD and PM are altitudes of the two triangles. We have to check if the relation ABPQ=ADPM\dfrac{AB}{PQ}=\dfrac{AD}{PM} holds or not.

As ΔABCΔPQR\Delta ABC\sim \Delta PQR, we know that the ratio of their corresponding sides is equal.
Thus, we have ABPQ=ACPR=BCQR\dfrac{AB}{PQ}=\dfrac{AC}{PR}=\dfrac{BC}{QR}.
We will now consider the triangles ΔABD\Delta ABD and ΔPQM\Delta PQM.
We will prove that the two triangles are similar.
As AD is the altitude of ΔABC\Delta ABC, we have ADBDAD\bot BD. So, we have ADB=90\angle ADB={{90}^{\circ }}.
Similarly, as PM is the altitude of ΔPQR\Delta PQR, we have PMQMPM\bot QM. So, we have PMQ=90\angle PMQ={{90}^{\circ }}.
Thus, PMQ=ADB=90\angle PMQ=\angle ADB={{90}^{\circ }}.
As we know that ΔABCΔPQR\Delta ABC\sim \Delta PQR. Thus, the corresponding angles of both the triangles are equal.
So, we have PQM=ABD\angle PQM=\angle ABD.
Thus, in ΔABD\Delta ABD and ΔPQM\Delta PQM, we have PMQ=ADB=90\angle PMQ=\angle ADB={{90}^{\circ }} and PQM=ABD\angle PQM=\angle ABD.
Using AA (Angle – Angle) Property, we have ΔABDΔPQM\Delta ABD\sim \Delta PQM.
As ΔABDΔPQM\Delta ABD\sim \Delta PQM, the ratio of length of sides of both the triangles is equal.
Thus, we have ABPQ=ADPM=BDQM\dfrac{AB}{PQ}=\dfrac{AD}{PM}=\dfrac{BD}{QM}.
So, the given statement is true.
Hence, the correct answer is 1.

Note: We can also prove that ΔABDΔPQM\Delta ABD\sim \Delta PQM by using the ASA (Angle Side Angle) Property as well. AA Property says that two corresponding angles of the triangles must be equal. ASA Property says that two corresponding angles and the sides between them of the two triangles must be equal.