Question

Triangle $ABC$ has vertices $(0, 0), (11, 60)$ and $(91, 0)$. If the line $y=kx$ cuts the triangle into $2$ two triangles of equal area, then $k$ is equal to

• A. $\frac{30}{51}$
• B. $\frac{4}{7}$
• C. $\frac{7}{4}$
• D. $\frac{30}{91}$

Answer 1

Answer: (A)

$\frac{30}{51}$

Answer 2

As the line divides the $\Delta ABC$ in equal area. Midpoint of AB(51, 30) which lies on $y=kx$ $\therefore$ $30=51k\Rightarrow k=\frac{30}{51}$