Solveeit Logo

Question

Question: Transverse waves of same frequency are generated in two steel wires A and B. The diameter of A is tw...

Transverse waves of same frequency are generated in two steel wires A and B. The diameter of A is twice of B and the tension in A is half that in B. The ratio of velocities of wave in A and B is

A

16mu:6mu321\mspace{6mu}:\mspace{6mu} 3\sqrt{2}

B

16mu:6mu221\mspace{6mu}:\mspace{6mu} 2\sqrt{2}

C

16mu:6mu21\mspace{6mu}:\mspace{6mu} 2

D

26mu:6mu1\sqrt{2}\mspace{6mu}:\mspace{6mu} 1

Answer

16mu:6mu221\mspace{6mu}:\mspace{6mu} 2\sqrt{2}

Explanation

Solution

v=Tm=Tπr2ρv = \sqrt{\frac{T}{m}} = \sqrt{\frac{T}{\pi r^{2}\rho}}

vTrvAvB=TATB.rBrA=12.12=122v \propto \frac{\sqrt{T}}{r} \Rightarrow \frac{v_{A}}{v_{B}} = \sqrt{\frac{T_{A}}{T_{B}}}.\frac{r_{B}}{r_{A}} = \sqrt{\frac{1}{2}}.\frac{1}{2} = \frac{1}{2\sqrt{2}}