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Question: Transmission lines transmit a voltage of \[V\] volt to our houses from power stations, then the powe...

Transmission lines transmit a voltage of VV volt to our houses from power stations, then the power PP supplied them is proportional to:
A. 1V\dfrac{1}{V}
B. VV
C. V2{V^2}
D. 1V2\dfrac{1}{{{V^2}}}

Explanation

Solution

The rate of dissipation of electric energy is called electric power. This energy dissipated in time tt is given by the product of current set up in the conductor, the potential difference across the conductor and the time period. By using this formula, the relation between voltage and power can be found out.

Formula Used:
The energy dissipated ww in time tt is given by: w=VItw = VIt
where, II is the current set up in the conductor, VV is the potential difference across the conductor and tt is the time.

Complete step by step answer:
The transmission lines transmit a voltage of VV volt to our houses from power stations. When a current II is set up in a conductor across which a potential difference VV is applied, the energy dissipated in time tt is given by,
w=VItw = VIt
Therefore, the electrical power dissipated will be,
P=wt=VItt=VIP = \dfrac{w}{t} = \dfrac{{VIt}}{t} = VI
Therefore, the power is directly proportional to voltage. Thai is,
PVP \propto V

Hence, option B is the correct answer.

Additional information:
The energy dissipated in time tt is given by w=VItw = VIt. This is derived from Joule’s Law equation. According to this equation, H=VItH = VIt where HH is the heat produced by the electric current, VV is the voltage, II is the current and tt is the time.

Note: The electrical power dissipated is P=VIP = VI.According to Ohm’s Law, V=IRV = IR. Substituting this in the above equation.
P=(IR)I=I2RP = \left( {IR} \right)I = {I^2}R
Then, if we substituteI=VRI = \dfrac{V}{R}. Therefore,

\Rightarrow P = {\left( {\dfrac{V}{R}} \right)^2}R \\\ \Rightarrow P= \dfrac{{{V^2}}}{{{R^2}}} \times R\\\ \Rightarrow P = \dfrac{{{V^2}}}{R}$$ Therefore, power can also be written as $$P = \dfrac{{{V^2}}}{R}$$ Thus if one goes by this formula, the power is directly proportional to the square of voltage. That is,$$P \propto {V^2}$$. The power is said to be 1 Watt when a current of 1 Ampere is set up in the conductor across which a potential difference of 1 Volt is applied.