Question

Trajectories of two projectiles are shown in figure. Let $T_{1}$ and $T_{2}$ be the time of flight and $u_{1}$ and $u_{2}$ are their speeds of projections, then

• A. $T_{2} >\, T_{1}$
• B. $T_{2} = T_{1}$
• C. $u_{1} > \, u_{2}$
• D. $u_{1} < \, u_{2}$

Answer 1

Answer: (B)

$T_{2} = T_{1}$

Answer 2

Since the height of both the projectiles are same, we have: $H _{1}= H _{2}$ $\frac{ u _{1}^{2} \sin ^{2} \theta_{1}}{2 g }=\frac{ u _{2}^{2} \sin ^{2} \theta_{2}}{2 g }$