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Question

Chemistry Question on The solid state

Total number or voids in 0.50.5 mole or compound forming hexagonal closed packed structure are

A

6.022×10236.022 \times 10^{23}

B

3.011×1023 3.011\times 10^{23}

C

9.033×1023 9.033\times 10^{23}

D

4.516×1023 4.516\times 10^{23}

Answer

9.033×1023 9.033\times 10^{23}

Explanation

Solution

In hexagonal close packed structure, there is 6 atoms per unit cell. ∴\therefore Number of octahedral voids =6=6 ∴\therefore Number of tetrahedral voids =2×6=12=2 \times 6=12 Total number of voids =6+12=18=6+12=18 ∴\therefore Total number of voids per atom =186=\frac{18}{6} =3= 3 ∵\because In 11 mole compound the total number of voids =3×6.023×1023=3 \times 6.023 \times 10^{23} ∴\therefore In 0.50.5 mole compound, the total number of voids =3×0.5×6.023×1023=3 \times 0.5 \times 6.023 \times 10^{23} =9.034×1023=9.034 \times 10^{23}