Question
Question: Total number of optical active stereoisomers of the following compound is : CH3 – CH = CH – CHCl – ...
Total number of optical active stereoisomers of the following compound is :
CH3 – CH = CH – CHCl – CH = C = CH – CH = CH – CH3
A
8
B
6
C
16
D
10
Answer
16
Explanation
Solution
Total no. of stereocentres (n) = 4
Total no. of optical isomers = 2n = 24 = 16