Question

To what radioactive family does $P{{b}^{207}}$ belongs?

• A. $T{{h}^{232}}$
• B. $N{{p}^{237}}$
• C. $A{{c}^{227}}$
• D. ${{U}^{238}}$

Answer 1

Answer: (C)

$A{{c}^{227}}$

Answer 2

$P{{b}^{207}}(207=4\times 51+3)$ belongs to 4n + 3 series or Actinium $(A{{c}^{227}})$ series. It starts from ${{U}^{235}}.$