Question
Physics Question on radiation
To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained: If V0 is almost zero, identify the correct statement:
A
The value of the resistance R is 1.5Ω
B
The emf of the battery is 1.5V and the value of R is 1.5Ω
C
The emf of the battery is 1.5V and its internal resistance is 1.5 Ω
D
The potential difference across the battery is 1.5V when it sends a current of 1000mA
Answer
The emf of the battery is 1.5V and its internal resistance is 1.5 Ω
Explanation
Solution
V=E−Ir when V=V0=0⇒0=E−Ir ∴E=r when I=0,V=E=1.5V ∴r=1.5Ω.