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Question: To synthesize the unsymmetrical alkyne \(\mathrm { CH } _ { 3 } - \mathrm { C } \equiv \mathrm { C ...

To synthesize the unsymmetrical alkyne

CH3−C≡C−CH2−CH3\mathrm { CH } _ { 3 } - \mathrm { C } \equiv \mathrm { C } - \mathrm { CH } _ { 2 } - \mathrm { CH } _ { 3 } the reagents needed would be.

A

Ethene, iodoethane, iodomethane and potassium

hydroxide

B

Acetaldehyde, 1-bromopropane and conc. H2SO4\mathrm { H } _ { 2 } \mathrm { SO } _ { 4 }

C

1, 2-dichloroethane, 1-propanol and alcoholic

potassium hydroxide

D

Ethyne, iodomethane, iodoethane and sodamide

Answer

Ethyne, iodomethane, iodoethane and sodamide

Explanation

Solution

CH=CH→NaNH2CH=C−Na+→−NalCH3lCH=C−CH3\mathrm { CH } = \mathrm { CH } \xrightarrow { \mathrm { NaNH } _ { 2 } } \mathrm { CH } = \mathrm { C } ^ { - } \mathrm { Na } ^ { + } \xrightarrow [ - \mathrm { Nal } ] { \mathrm { CH } _ { 3 } \mathrm { l } } \mathrm { CH } = \mathrm { C } - \mathrm { CH } _ { 3 }