To send 10% of main current through a moving coil galvanomet... | Physics | SolveeIt | Solveeit

Today, August 18

Question

To send 10% of main current through a moving coil galvanometer of resistance $99\,\Omega$ the shunt required is

A

$9\,\Omega$

B

$11\,\Omega$

C

$10\,\Omega$

D

$9.9\,\Omega$

Answer

$11\,\Omega$

Explanation

Solution

105 = G + S $i.e.$ 9S = G = 99 $i.e.$ S = 11