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Question: To remove myopia (short sightedness) a lens of power 0.66 D is required. The distant point of the ey...

To remove myopia (short sightedness) a lens of power 0.66 D is required. The distant point of the eye is approximately

A

100 cm

B

150 cm

C

50 cm

D

25 cm

Answer

150 cm

Explanation

Solution

Far point of the eye = focal length of the lens

=100P=1000.66=151 cm= \frac { 100 } { P } = \frac { 100 } { 0.66 } = 151 \mathrm {~cm}