Question

To prepare 2 $dm^3$ of decinormal solution of oxalic acid, the mass of oxalic acid required is

• A. 6.3 g
• B. 0.63 g
• C. 12.6 g
• D. 1.26 g

Answer 1

Answer: (C)

12.6 g

Answer 2

Normality = $\frac{1}{10}$ N Volume= ${2 \, dm^3}$ Now, $N = \frac{w}{ { E wt. \times Volume \, in\, L \, or\, dm^3 }}$ $\Rightarrow \:\: w = N \times { Eq . wt \times Volume}$ � � $= \frac{1}{10} \times 63 \times 2 = 12.6 \,g$