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Question

Physics Question on Oscillations

To make the frequency double of a spring oscillator, we have to

A

reduce the mass to one-fourth

B

quadruple the mass

C

double the mass

D

half the mass

Answer

reduce the mass to one-fourth

Explanation

Solution

The frequency of spring oscillator is v=12π(km)v=\frac{1}{2 \pi} \sqrt{\left(\frac{k}{m}\right)} v(1m)\Rightarrow v \propto \sqrt{\left(\frac{1}{m}\right)} Hence, v1v2=(m2m1)\frac{v_{1}}{v_{2}}=\sqrt{\left(\frac{m_{2}}{m_{1}}\right)} or m2m1=(v1v2)2\frac{m_{2}}{m_{1}}=\left(\frac{v_{1}}{v_{2}}\right)^{2} =(v2v)=14=\left(\frac{v}{2 v}\right)=\frac{1}{4} m2=m14\therefore {m}_{2}=\frac{m_{1}}{4}