Question

To get real magnified image in convex lens, the object position is:
A. In between lens and F
B. in between F and 2F
C. at 2F
D. beyond 2F

Answer 1

Here in the question it is given that the image is real and magnified. So, from this statement one thing is clear that the image will be inverted and will be situated at the other side of the lens.

Complete step by step answer:
So, from the question we have the nature of the image which will be formed by the convex lens will be as follows-
1. image will be real
2. image will be inverted
3. image will be larger than the object which is called a magnified image of any object.
So to get the image having above properties and nature we are considering a situation in which we are putting the object in between the focal point, $F$ and $2F$.

In this situation, the light ray coming from the object and parallel to the principal axis will go through the focus of the lens at the other side of the lens and the ray which is passing through the centre of curvature of the lens will pass without any deflection. These both rays will meet at a point beyond the point $2F$ at the other side of the lens and will form an image below the principal axis.
So here we see that the image is fulfilling all the conditions required in the question when it is placed in between $F$ and $2F$.

So, the correct answer is “Option B”.

Note: Here we see that we are getting a magnified image of the given object. Magnification formula to the correct magnification ratio with respect to the size of the object, so the magnification formula says that the magnification is the ratio of the height of the image to the height of the object when they are measured in the planes that are perpendicular to the principal axis.
Hence if $m =$ magnification
${h_i}$ =height of the image
${h_o}$ =height of the object
So,$m = \dfrac{{{h_i}}}{{{h_o}}}$.