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Question: To get maximum current through a resistance of 2.5 Ω, one can use m rows of cells, each row having n...

To get maximum current through a resistance of 2.5 Ω, one can use m rows of cells, each row having n cells. The internal resistance of each cell is 0.5 Ω. What are the values of n and m if the total number of cells is 45?

A

m= 3, n = 15

B

m= 5, n = 9

C

m= 9, n = 5

D

m= 15, n = 3

Answer

m= 3, n = 15

Explanation

Solution

R = 2.5 Ω, r = 0.5 Ω

no. of rows = m , no of cells in each row = n

i = nER+nr/m\frac{nE}{R + nr/m} total cells ⇒ mn = 45

for max. current ;R = nr/m, mR = nr

n = 5m , 5m2 = 45, m = 3, n = 15