Question

To generate a power of 3.2 mega watt, the number of fissions of $U^{235}$ per minute is.

(Energy released per fission = 200MeV,

$1eV = 1.6 \times 10^{- 19}J)$

• A. $6 \times 10^{18}$
• B. $6 \times 10^{17}$
• C. $10^{17}$
• D. $6 \times 10^{16}$

Answer 1

Answer: (A)

$6 \times 10^{18}$

Answer 2

Number of fissions per second

$= \frac{Power\mspace{6mu} output}{Energy\mspace{6mu} released\mspace{6mu} per\mspace{6mu} fission}$

$= \frac{3.2 \times 10^{6}}{200 \times 10^{6} \times 1.6 \times 10^{- 19}} = 1 \times 10^{17}$

$\Rightarrow$Number of fission per minute $= 60 \times 10^{17} = 6 \times 10^{18}$.