Question

To evaluate the double integral $\int_0^8\left(\int\limits_{y/2}^{(y/2)+1}\left(\frac{2x-y}{2}\right)dx\right)dy$, we make the substitution $u=\frac{2x-y}{2}$and $v=\frac{y}{2}$. The integral will reduce to

• A. $\int_0^4(\int_0^22udu)dv$
• B. $\int_0^4(\int_0^12udu)dv$
• C. $\int_0^4(\int_0^1udu)dv$
• D. $\int_0^4(\int_0^{21}2udu)dv$

Answer 1

Answer: (B)

$\int_0^4(\int_0^12udu)dv$

Answer 2

The correct answer is(B): $\int_0^4(\int_0^12udu)dv$