Question
Question: To estimate ‘g’ (from \[g=4{{\pi }^{2}}\dfrac{L}{{{T}^{2}}}\]), error in measurement of L is \[\pm 2...
To estimate ‘g’ (from g=4π2T2L), error in measurement of L is ±2% and error in measurement of T is ±3%. The error is estimated ‘g’ will be –
A) ±8%
B) ±6%
C) ±3%
D) ±5%
Solution
We need to find the relation between the percentage errors involved in each physical quantity in the given physical quantity with the percentage error involved in the physical quantity. We can find the solution for this problem using this relation.
Complete answer:
The dimensional formula of a physical phenomenon gives the idea on the physical quantities involved or related to them. They also give the operations involved in the relation, thus giving us the idea to calculate the errors involved with the calculation of the physical phenomenon.
Let us recap the error analysis method for different mathematical operations.
For, z=x−y, the error involved is
±∂z=±∂x±∂y
For,d=cab, the error involved is
d∂d=a∂a+b∂b+c∂c
For, d=crapbq, the error involved is
d∂d=ap∂a+bq∂b+cr∂c –(1)
Now, let us consider the given physical quantity. It is given that the acceleration due to gravity can be related to a number of other physical quantities as –
g=4π2T2L
We are also given the percentage errors involved in the measurement of length ‘L’ and the measurement of time ‘T’. We can use the above relations to find the percentage error of the acceleration due to gravity as –