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Question

Physics Question on Capacitors and Capacitance

To establish an instantaneous current of 2A2 A through a 1μF1 \mu F capacitor; the potential difference across the capacitor plates should be changed at the rate of :

A

2×104V/s2 \times 10^4V/s

B

4×106V/s4 \times 10^6V/s

C

2×106V/s2 \times 10^6V/s

D

4×104V/s4 \times 10^4V/s

Answer

2×106V/s2 \times 10^6V/s

Explanation

Solution

As, C=QV=ItVC=\frac{Q}{V}=\frac{It}{V} Vt=IC=21×106\Rightarrow \frac{V}{t}=\frac{I}{C}=\frac{2}{1\times10^{-6}} =2×106V/s=2\times10^{6}\,V/s