Question

To deposit 0.6354 gm of copper by electrolysis of aqueous cupric sulphate solution, the amount of electricity required (in coulombs) is.

• A. 9650
• B. 4825
• C. 3860
• D. 1930

Answer 1

Answer: (D)

1930

Answer 2

$Cu^{+ +} + 2e^{-} \rightarrow Cu$

$E_{Cu} = \frac{63.54}{2} = 31.77$

Amount of electricity required to deposit .6354 gm of Cu $= \frac{96500 \times 0.6354}{31.77} = 1930Coulombs$.