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Question

Question: To break a wire, a force of \(3 \times 10 ^ { 3 } \mathrm {~kg} / \mathrm { m } ^ { 3 }\), then the ...

To break a wire, a force of 3×103 kg/m33 \times 10 ^ { 3 } \mathrm {~kg} / \mathrm { m } ^ { 3 }, then the length of the wire which will break by its own weight will be

A

34 m

B

30 m

C

300 m

D

3 m

Answer

34 m

Explanation

Solution

Length of the wire which will break by its own weight L=Pdg=1063×103×10=1003L = \frac { P } { d g } = \frac { 10 ^ { 6 } } { 3 \times 10 ^ { 3 } \times 10 } = \frac { 100 } { 3 } m ≃ 34 m.