Question

to a bird in air, a fish appears to be 60cm below water. if mu=4/3 find actual depth of fish

Answer 1

80 cm

Answer 2

When an object in a denser medium (water) is viewed from a rarer medium (air), the apparent depth is less than the real depth. The relationship between real depth (d), apparent depth (d'), and the refractive index (μ) of the denser medium with respect to the rarer medium is given by:

$\mu = \frac{\text{Real Depth}}{\text{Apparent Depth}}$ $\mu = \frac{d}{d'}$

Given: Apparent depth, d' = 60 cm Refractive index of water with respect to air, μ = 4/3

Substitute the values into the formula: $\frac{4}{3} = \frac{d}{60}$

Now, solve for the real depth, d: $d = \frac{4}{3} \times 60$ $d = 4 \times 20$ $d = 80 \text{ cm}$

Thus, the actual depth of the fish is 80 cm.