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Question: TlAl (SO<sub>4</sub>)<sub>2</sub> . xH<sub>2</sub>O is bcc with 'a'= 1.22 nm. If the density of the ...

TlAl (SO4)2 . xH2O is bcc with 'a'= 1.22 nm. If the density of the solid is 2.32 g/cc, then the value of x is

(Given : NA = 6 × 1023; at. wt. : Tl = + 204, Al = 27, S = 32, O = 16, H = 1)

A

2

B

4

C

47

D

70

Answer

47

Explanation

Solution

2.32 = 2×M6×1023×(1.22)3×10–21\frac{2 \times M}{6 \times 10^{23} \times (1.22)^{3} \times 10^{–21}}

\ M = 1264 &x≅47\begin{matrix} x \cong 47 \end{matrix}