Question

Tischenko reaction is a modification of:
A: Aldol condensation
B: Pinacol-Pinacolone reaction
C: Cannizzaro reaction
D: Claisen condensation

Answer 1

Organic reactions are the reactions involving organic compounds. Organic compounds are the compounds which contain carbons and its derivatives. Tischenko reaction involves the disproportionation of an aldehyde in the presence of an alkoxide.

Complete step by step answer:
Tischenko reaction is an organic chemical reaction in which there is a disproportionation of aldehyde in presence of alkoxide. The alkoxide is the conjugate base of alcohol which consists of an organic compound bonded to negatively charged oxygen atom.
In aldol, condensation enol reacts with a carbonyl compound. But in the tishchenko reaction aldehyde is involved therefore aldol condensation is not our answer.
Pinacol-Pinacolone is a rearrangement for converting $1,2 -$ diol to carbonyl compounds. This rearrangement takes place in an acidic medium. So this is also not the answer.
In the Cannizzaro reaction base is sodium hydroxide and then the oxidation product (in which there is the loss of electron) is a carboxylic acid and the reduction product (in which there is a gain of the electron) is alcohol. In the tishchenko reaction, we use a conjugate base of alcohol so we can consider this as an answer but let’s see what the next option is.
Claisen condensation is a carbon-carbon bond-forming reaction that occurs between two esters or between one ester and one carbonyl compound in presence of a strong base resulting in the formation of $\beta -$ keto ester. Therefore this option is also not the answer.
So the correct answer is option C that is the Cannizzaro reaction.

Note:
Like tishchenko reaction Wurtz fittig reaction is also a type of organic reaction in which aromatic ring and alkyl chain are joined together. Alkyl halide and aryl halide react with sodium in the presence of dry ether in this reaction.