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Question: Time taken by the projectile to reach A to B is t. Then the distance AB is equal to – ![](https://c...

Time taken by the projectile to reach A to B is t. Then the distance AB is equal to –

A

ut3\frac{ut}{\sqrt{3}}

B

3ut2\frac{\sqrt{3}ut}{2}

C

3\sqrt{3}ut

D

2 ut

Answer

ut3\frac{ut}{\sqrt{3}}

Explanation

Solution

Horizontal component of velocity

uH = u cos 600 = u2\frac{u}{2}

\ AC = (uH)t = ut2\frac{ut}{2}