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Question: Time taken by an object falling from rest to cover the height of \(h_{1}\) and \(h_{2}\) is respecti...

Time taken by an object falling from rest to cover the height of h1h_{1} and h2h_{2} is respectively t1t_{1} and t2t_{2} then the ratio of t1t_{1} to t2t_{2} is

A

h16mu:6muh2h_{1}\mspace{6mu}:\mspace{6mu} h_{2}

B

h16mu:6muh2\sqrt{h_{1}}\mspace{6mu}:\mspace{6mu}\sqrt{h_{2}}

C

h16mu:6mu2h2h_{1}\mspace{6mu}:\mspace{6mu} 2h_{2}

D

2h1 : h2

Answer

h16mu:6muh2\sqrt{h_{1}}\mspace{6mu}:\mspace{6mu}\sqrt{h_{2}}

Explanation

Solution

t=2hgt1t2=h1h2t = \sqrt{\frac{2h}{g}} \Rightarrow \frac{t_{1}}{t_{2}} = \sqrt{\frac{h_{1}}{h_{2}}}