Time period of SHM is given by T = 2(\pi) \[displacement / a... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Time period of SHM is given by T = 2 $\pi$ [displacement / acceleration] $^{1/2}$ . When displacement increases, the time period

A

increases

B

decreases

C

remains unchanged

D

may increase or decrease

Answer

remains unchanged

Explanation

Solution

Increase in displacement produces corresponding increase in acceleration