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Question

Physics Question on simple harmonic motion

Time period of a spring mass system is TT. If this spring is cut into two parts whose lengths are in the ratio 1:31:3 and the same mass is attached to the longer part, the new time period will be

A

32T\sqrt{\frac{3}{2}}T

B

T3\frac{T}{\sqrt{3}}

C

3T2\frac{\sqrt{3}T}{2}

D

3T\sqrt{3}T

Answer

T3\frac{T}{\sqrt{3}}

Explanation

Solution

The spring mass system oscillate in SHMSHM, its time period is given by T=2πmkT=2 \pi \sqrt{\frac{m}{k}} When spring is cut into ratio 1:31: 3, the new time constant is k=3kk^{\prime}=3 k TT=3kkT=T3\therefore \frac{T}{T^{\prime}}=\sqrt{\frac{3 k}{k}} \Rightarrow T^{\prime}=\frac{T}{\sqrt{3}}