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Question

Physics Question on Oscillations

Time period of a simple pendulum is TT. If its length increases by 2%2\%, the new time period becomes

A

0.98 T

B

1.02 T

C

0.99 T

D

1.01 T

Answer

1.01 T

Explanation

Solution

Tl1/2T \propto l^{1 / 2} ΔTT=12(Δll) \Rightarrow \frac{\Delta T}{T} =\frac{1}{2}\left(\frac{\Delta l}{l}\right) ΔTT=12(2%)=1%\frac{\Delta T}{T} =\frac{1}{2}(2 \%)=1 \% TTT=1100\Rightarrow \frac{T'-T}{T} =\frac{1}{100} T=T+0.01T\Rightarrow T'=T+0.01 \,T T=1.01T \Rightarrow T' =1.01 \, T