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Question: Through two parallel wires A and B, 10 and 2 ampere of currents are passed respectively in opposite ...

Through two parallel wires A and B, 10 and 2 ampere of currents are passed respectively in opposite direction. If the wire A is infinitely long and the length of the wire B is 2 m, the force on the conductor B, which is situated at 10 cm distance from A will be

A

B

4×10−7N4 \times 10 ^ { - 7 } N

C

4×10−5N4 \times 10 ^ { - 5 } N

D

4π×10−7N4 \pi \times 10 ^ { - 7 } N

Answer

Explanation

Solution

F=μ04π⋅2i1i2a×lF = \frac { \mu _ { 0 } } { 4 \pi } \cdot \frac { 2 i _ { 1 } i _ { 2 } } { a } \times l ⇒F=10−7×2×10×2(10×10−2)×2=8×10−5 N\Rightarrow F = 10 ^ { - 7 } \times \frac { 2 \times 10 \times 2 } { \left( 10 \times 10 ^ { - 2 } \right) } \times 2 = 8 \times 10 ^ { - 5 } \mathrm {~N}