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Question: Three vertices of a parallelogram taken in order are (–1, –6), (2, –5) and (7, 2) The fourth vertex ...

Three vertices of a parallelogram taken in order are (–1, –6), (2, –5) and (7, 2) The fourth vertex is –

A

(1, 4)

B

(4, 1)

C

(1, 1)

D

(4, 4)

Answer

(4, 1)

Explanation

Solution

D = A + C – B

(x, y) = (–1 + 7 – 2, – 6 + 2 + 5)

= (4, 1)