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Question

Physics Question on Newtons law of gravitation

Three uniform spheres of mass M and radius R earth are kept in such a way that each touches the other two. The magnitude of the gravitational force on any of the spheres due to the other two is

A

34GM2R2\frac{\sqrt3}{4}\frac{GM^2}{R^2}

B

32GM2R2\frac{3}{2}\frac{GM^2}{R^2}

C

3GM2R2\frac{\sqrt3GM^2}{R^2}

D

32GM2R2\frac{\sqrt3}{2}\frac{GM^2}{R^2}

Answer

34GM2R2\frac{\sqrt3}{4}\frac{GM^2}{R^2}

Explanation

Solution

Force between any two spheres will be F=G(M)(M)(2R)2=GM24R2F =\frac{G(M) (M) }{(2R)^2} = \frac{GM^2}{4R^2} The two forces of equal magnitude F are acting at angle 6060^\circ on any o f the sphere Fnet=F2+F2+2(F)(F)cos60=3FF_{net} = \sqrt{F^2 + F^2 + 2(F) (F) \, cos \, 60^\circ} = \sqrt{3}F