Solveeit Logo

Question

Question: Three six-faced dice are thrown together. The probability that the sum of the numbers appearing on t...

Three six-faced dice are thrown together. The probability that the sum of the numbers appearing on the dice is k

(9 £ k £ 14), is -

A

B

k23k+2432\frac { \mathrm { k } ^ { 2 } - 3 \mathrm { k } + 2 } { 432 }

C

D

None of these

Answer

Explanation

Solution

Favourable number of elementary events

= Coeff. of xk–3 in (1 – x6)3 (1 – x)–3

= Coeff. of xk–3 in (1 – 3C1x6 + …) (1 – x)–3 [Q 9 £ k £ 14, \ 6 £ k – 3 £ 11]

= Coeff. of xk – 3 in (1 – x)–33C1 (Coeff. of xk – 9 in (1 – x)–3)

= k–3+3–1C3–13C1 × k–9+3–1C3–1

= k–1C2 – 3. k–7C2

= – 3. = 21k – k2 – 83. The total number of elementary events associated to the random experiment of throwing three dice is 6 × 6 × 6 = 63.

Hence, the probability of the required event

= Hence, (1) is correct answer