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Question: Three rods of same dimensions are arranged as shown in figure they have thermal conductivities K<sub...

Three rods of same dimensions are arranged as shown in figure they have thermal conductivities K1, K2 and K3. The points P and Q are maintained at different temperatures for the heat to flow at the same rate along PRQ and PQ then which of the following option is correct

A

K3=12(K1+K2)K_{3} = \frac{1}{2}(K_{1} + K_{2})

B

K3=K1+K2K_{3} = K_{1} + K_{2}

C

K3=K1K2K1+K2K_{3} = \frac{K_{1}K_{2}}{K_{1} + K_{2}}

D

K3=2(K1+K2)K_{3} = 2(K_{1} + K_{2})

Answer

K3=K1K2K1+K2K_{3} = \frac{K_{1}K_{2}}{K_{1} + K_{2}}

Explanation

Solution

Rate of flow of heat along PQ (dQdt)PQ=K3AΔθl\left( \frac{dQ}{dt} \right)_{PQ} = \frac{K_{3}A\Delta\theta}{l} ….(i)

Rate of flow of heat along PRQ (dQdt)PRQ=KsAΔθ2l\left( \frac{dQ}{dt} \right)_{PRQ} = \frac{K_{s}A\Delta\theta}{2l}

Effective conductivity for series combination of two rods of

same length Ks=2K1K2K1+K2K_{s} = \frac{2K_{1}K_{2}}{K_{1} + K_{2}}

So (dQdt)PRQ=2K1K2K1+K2.AΔθ2l=K1K2K1+K2.AΔθl\left( \frac{dQ}{dt} \right)_{PRQ} = \frac{2K_{1}K_{2}}{K_{1} + K_{2}}.\frac{A\Delta\theta}{2l} = \frac{K_{1}K_{2}}{K_{1} + K_{2}}.\frac{A\Delta\theta}{l}

Equating (i) and (ii) K3=K1K2K1+K2K_{3} = \frac{K_{1}K_{2}}{K_{1} + K_{2}}