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Question: Three rods of identical cross-sectional area and made from the same metal form the sides of an isosc...

Three rods of identical cross-sectional area and made from the same metal form the sides of an isosceles triangle ABC right angled at B. The points A and B are maintained at temperatures T and 2T\sqrt{2}T respectively in the steady state. Assuming that only heat conduction takes place, temperature of point C will be –

A

3T2+1\frac{3T}{\sqrt{2} + 1}

B

T2+1\frac{T}{\sqrt{2} + 1}

C

T3(21)\frac{T}{\sqrt{3}(\sqrt{2} - 1)}

D

T21\frac{T}{\sqrt{2} - 1}

Answer

3T2+1\frac{3T}{\sqrt{2} + 1}

Explanation

Solution

kA(2Tθ)l\frac{kA(\sqrt{2}T - \theta)}{\mathcal{l}} = kA(θT)2l\frac{kA(\theta - T)}{\sqrt{2}\mathcal{l}}

Ž 2T – 2\sqrt{2}q = q – T

3T = (1+2)(1 + \sqrt{2}) q

q = 3T1+2\frac{3T}{1 + \sqrt{2}}