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Question

Physics Question on Heat Transfer

Three rods of copper , brass and steel are welded together to form a Y-shaped structure .Area of cross -section of each rod is 4cm24cm^2.End of copper rod is maintained at 100C100^{\circ}C whereas ends of brass and steel are kept at 0C0^{\circ C} Lengths of the copper, brass and steel rods are 46,13 and 12 cm respectively The rods are thermally insulated from surroundings except at ends.Thermal conductivities of copper , brass and steel are 092 , 0.26 and 0.12 in CGS units , respectively .Rate of heat flow throught cooper rod is

A

1.2 cal /s

B

2.4 cal/s

C

4.8 cal/s

D

6.0 cal/s

Answer

4.8 cal/s

Explanation

Solution

Q=Q1+Q2Q= Q_{1}+Q_{2} 0.92×4(100T)46=0.26×4×(T0)13+0.12×4×T12\frac{0.92 \times 4(100-T)}{46}=\frac{0.26 \times 4 \times(T-0)}{13}+\frac{0.12 \times 4 \times T}{12} 2002T=2T+T\Rightarrow 200-2 T=2 T+T T=40C\Rightarrow T=40^{\circ} C Q=0.92×4×6046\Rightarrow Q=\frac{0.92 \times 4 \times 60}{46} =4.8cal/s=4.8\, cal / s