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Question: Three rods each of length L and mass M are placed along X, Y and Z-axes in such a way that one end o...

Three rods each of length L and mass M are placed along X, Y and Z-axes in such a way that one end of each of the rod is at the origin. The moment of inertia of this system about Z axis is

A

2ML23\frac{2ML^{2}}{3}

B

4ML23\frac{4ML^{2}}{3}

C

5ML23\frac{5ML^{2}}{3}

D

ML23\frac{ML^{2}}{3}

Answer

2ML23\frac{2ML^{2}}{3}

Explanation

Solution

Moment of inertia of the system about z-axis can be find out by calculating the moment of inertia of individual rod about z-axis

I1=I2=ML23I_{1} = I_{2} = \frac{ML^{2}}{3} because z-axis is the edge of rod 1 and 2 and I3=0I_{3} = 0 because rod in lying on z-axis

\therefore Isystem=I1+I2+I3=ML23+ML23+0=2ML23I_{\text{system}} = I_{1} + I_{2} + I_{3} = \frac{ML^{2}}{3} + \frac{ML^{2}}{3} + 0 = \frac{2ML^{2}}{3}.