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Question: Three rods A, B and C have the same dimensions. Their thermal conductivities are k<sub>A</sub>, k<su...

Three rods A, B and C have the same dimensions. Their thermal conductivities are kA, kB, and kCrespectively. A and B are placed end to end, with their free ends kept at certain temperature difference. C is placed separately with its ends kept at same temperature difference. The two arrangements conduct heat at the same rate. kC must be equal to –

A

kA + kB

B

kAkBkA+kB\frac{k_{A}k_{B}}{k_{A} + k_{B}}

C

12\frac{1}{2} (kA + kB)

D

2kAkBkA+kB\frac{2k_{A}k_{B}}{k_{A} + k_{B}}

Answer

kAkBkA+kB\frac{k_{A}k_{B}}{k_{A} + k_{B}}

Explanation

Solution

T1T2LkAA+LkBA\frac{T_{1}–T_{2}}{\frac{L}{k_{A}A} + \frac{L}{k_{B}A}} = T1T2LkCA\frac{T_{1}–T_{2}}{\frac{L}{k_{C}A}}

kAkBkA+kB\frac{k_{A}k_{B}}{k_{A} + k_{B}} = kC