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Question

Physics Question on Current electricity

Three resistances P,Q,RP, Q, R each of 2Ω2\, \Omega and an unknown resistance SS form the four arms of a Wheatstone bridge circuit. When a resistance of 6Ω6\, \Omega is connected in parallel to SS the bridge gets balanced. What is the value of SS ?

A

3Ω3\, \Omega

B

6Ω6\, \Omega

C

1Ω1\, \Omega

D

2Ω2\, \Omega

Answer

3Ω3\, \Omega

Explanation

Solution

for balanced wheatstone bridge circuit
22=2(6SS+6)\frac{2}{2}=\frac{2}{\left(\frac{6 S }{ S +6}\right)}
S+6=3S\Rightarrow S +6=3 S
S=3Ω\Rightarrow S =3 \Omega