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Question

Physics Question on Resistance

Three resistances of values 2Ω\Omega, 3Ω\Omega and 6Ω\Omega are to be connected to produce an effective resistance of 4Ω\Omega . This can be done by connecting

A

6Ω\Omega resistance in series with the parallel combination of 2Ω\Omega and 3Ω\Omega

B

3Ω\Omegaresistance in series with the parallel combination of 2Ω\Omega and 6Ω\Omega

C

2Ω\Omegaresistance in series with the parallel combination of 3Ω\Omega and 6Ω\Omega

D

2Ω\Omega resistance in parallel with the parallel combination of 3Ω\Omega and 6Ω\Omega

Answer

2Ω\Omegaresistance in series with the parallel combination of 3Ω\Omega and 6Ω\Omega

Explanation

Solution

Parallel combination of 3Ω\Omega and 6Ω\Omega gives effective resistance,
Rp=3X63+6=189=2ΩR_p=\frac{3 X 6}{3+6}=\frac{18}{9}=2\OmegaThis in series with
2 Ω\Omega gives net ressistance as 4 Ω\Omega