Question

Three resistances of one ohm each are connected in parallel. Such connection is again connected with $2/3\Omega$ resistor in series. The resultant resistance will be

• A. $\frac{5}{3}\Omega$
• B. $\frac{3}{2}\Omega$
• C. $1\Omega$
• D. $\frac{2}{3}\Omega$

Answer 1

Answer: (C)

$1\Omega$

Answer 2

Resistance of 1 ohm group $= \frac{R}{n} = \frac{1}{3}\Omega$

This is in series with $\frac{2}{3}\Omega$resistor.

$\therefore$Total resistance $= \frac{2}{3} + \frac{1}{3} = \frac{3}{3}\Omega = 1\Omega$